1990 United States Senate election in Rhode Island

1990 United States Senate election in Rhode Island
November 6, 1990
 
Nominee Claiborne Pell Claudine Schneider
Party Democratic Republican
Popular vote 225,105 138,947
Percentage 61.83% 38.17%
Pell:      50–60%      60–70%      70–80%
Schneider:      50–60%
U.S. senator before election

Claiborne Pell
Democratic

Elected U.S. Senator

Claiborne Pell
Democratic

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The 1990 Rhode Island United States Senate election was held on November 6, 1990, to select the U.S. Senator from the state of Rhode Island. Democratic U.S. Senator Claiborne Pell decided to seek re-election and defeated Republican Representative Claudine Schneider in a landslide.[1]

Candidates

Democrat

Republican

Results

United States Senate election in Rhode Island, 1990[2]
Party Candidate Votes % ±%
Democratic Claiborne Pell (Incumbent) 225,105 61.83% −10.83%
Republican Claudine Schneider 138,947 38.17% +10.83%
Majority 86,158 23.67% −21.65%
Turnout 364,062
Democratic hold Swing

See also

References

  1. ^ "Our Campaigns - RI US Senate Race - Nov 06, 1990".
  2. ^ Dendy, Dallas L. "Statistics of the Congressional Election of November 6, 1990" (PDF).
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