1812 United States presidential election in Rhode Island|
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The 1812 United States presidential election in Rhode Island took place as part of the 1812 United States presidential election. Voters chose four representatives, or electors, to the Electoral College, who voted for president and vice president.
Rhode Island voted for the Federalist candidate, DeWitt Clinton, over the Democratic-Republican candidate, James Madison. Clinton won Rhode Island by a margin of 65.93%. With Madison's second loss (the first one was 1808), this marked the first time that a candidate or an incumbent president lost two presidential elections in Rhode Island.
Results
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Notes
- ^ While commonly labeled as the Federalist candidate, Clinton technically ran as a Democratic-Republican and was not nominated by the Federalist party itself, the latter simply deciding not to field a candidate. This did not prevent endorsements from state Federalist parties (such as in Pennsylvania), but he received the endorsement from the New York state Democratic-Republicans as well.
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