1868 Rhode Island gubernatorial election

1868 Rhode Island gubernatorial election
	1 April 1868
	County results; Burnside: 60–70% 80–90%
Governor before election; Ambrose Burnside; Republican	Elected Governor ; Ambrose Burnside; Republican

The 1868 Rhode Island gubernatorial election was held on 1 April 1868 in order to elect the governor of Rhode Island. Incumbent Republican governor Ambrose Burnside won re-election against Democratic nominee Lyman Pierce in a rematch of the 1866 and 1867 election.^[1]

General election

On election day, 1 April 1868, incumbent Republican governor Ambrose Burnside won re-election by a margin of 6,648 votes against his opponent Democratic nominee Lyman Pierce, thereby retaining Republican control over the office of Governor. Burnside was sworn in for his third term on 4 May 1868.

Results

Rhode Island gubernatorial election, 1868^[2]
Party		Candidate	Votes	%
	Republican	Ambrose Burnside (incumbent)	10,038	63.61
	Democratic	Lyman Pierce	5,731	36.32
		Scattering	11	0.07
Total votes			15,780	100.00
	Republican hold

References

^ "Ambrose Burnside". National Governors Association. Retrieved April 7, 2024.
^ United States Gubernatorial Elections 1861-1911 (Michael J. Dubin) Page 478

[nga-1] "Ambrose Burnside". National Governors Association. Retrieved April 7, 2024.

[2] United States Gubernatorial Elections 1861-1911 (Michael J. Dubin) Page 478

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