1989 Cleveland mayoral election|
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The 1989 Cleveland mayoral election took place on November 7, 1989, to elect the Mayor of Cleveland, Ohio. The election was officially nonpartisan, with the top two candidates from the October 3 primary advancing to the general election.
Both candidates who advanced to the runoff were African American and Democrats.[1]
Candidates
Primary election
General election
References
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U.S. House |
- Alabama
- California
- Florida
- Indiana
- Mississippi
- Texas
- Wyoming
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Governors | |
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State legislatures | |
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Mayors |
- Atlanta, GA
- Buffalo, NY
- Burlington, VT
- Chicago, IL (special)
- Houston, TX
- Los Angeles, CA
- Manchester, NH
- New York City, NY
- Pittsburgh, PA
- St. Louis, MO
- Springfield, MA (sp)
- Springfield, MA
- Worcester, MA
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State-wide |
- Alabama
- California
- Florida
- Illinois
- Indiana
- Massachusetts
- Mississippi
- New Jersey
- New York
- Ohio
- Pennsylvania
- Texas
- Vermont
- Virginia
- Wyoming
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