1958 Wimbledon Championships – Boys' singles

Boys' singles
1958 Wimbledon Championships
Champion Butch Buchholz
Runner-up Premjit Lall
Score6–1, 6–3

Jimmy Tattersall was the defending champion, but lost to Premjit Lall in the semifinals.

Butch Buchholz defeated Lall in the final, 6–1, 6–3 to win the boys' singles tennis title at the 1958 Wimbledon Championships.[1]

Draw

Key

Finals

Semifinals Final
          
Butch Buchholz 6 8 6
Ronnie Barnes 8 6 3
Butch Buchholz 6 6
Premjit Lall 1 3
Premjit Lall 6 6
Jimmy Tattersall 2 2

Top half

First round Second round Quarterfinals Semifinals
Butch Buchholz 6 6
Lassie Lincoln 4 1
E Buchholz 6 6
J Leschly 3 1
Karim Fawaz 3 2
Jan Leschly 6 6
E Buchholz 6 8 6
R Barnes 8 6 3
Guiliano Fanfani 0 1
Ronnie Barnes 6 6 R Barnes 6 6
A Ahmad 0 0 R Barnes 7 14
A Abreu 6 3 6 A Potanin 5 12
C Coste 3 6 4 A Abreu 1 0
Alain Bresson 3 6 A Potanin 6 6
Andrei Potanin 6 8

Bottom half

First round Second round Quarterfinals Semifinals
José Luis Arilla 6 6
Srdjan Jelić 0 0 JL Arilla 3 7 6
Thomas Hallberg 6 6 T Hallberg 6 5 2
Bernard Auberson 1 1 JL Arilla 4 5
TE Vold 1 3 P Lall 6 7
Michael Hickey 6 6 M Hickey 0 1
Premjit Lall 6 6
P Lall 6 6
J Tattersall 2 2
Piotr Jamroz 7 6
Jan Beukers 5 3
P Jamroz 6 2 4
J Tattersall 2 6 6
Peter Pokorny 0 5
Jimmy Tattersall 6 7

References

  1. ^ "Boys' Singles Finals 1947-2017". wimbledon.com. Wimbledon Championships. Retrieved 13 August 2017.