1890 Belgian general election|
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First party
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Second party
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| Leader
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Auguste Beernaert
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| Party
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Catholic
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Liberal
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| Leader's seat
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Candidate for PM
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| Seats before
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98 seats
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40 seats
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| Seats won
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29
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40
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| Seats after
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94
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44
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| Seat change
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4
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4
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| Popular vote
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17,253
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20,829
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| Percentage
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45.15%
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54.51%
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Partial general elections were held in Belgium on 10 June 1890.[1][2] In the elections for the Chamber of Representatives the result was a victory for the Catholic Party, which won 94 of the 138 seats.[2]
Under the alternating system, elections were held in only four out of the nine provinces: Hainaut, Limburg, Liège and East Flanders. Thus, only 69 seats out of the 138 were up for election. Additionally, a special election was held in Neufchâteau on 3 June 1890.[3]
Results
Chamber of Representatives
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| Party | Votes | % | Seats |
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| Won | Total | +/– |
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| Liberal Party | 20,829 | 54.51 | 40 | 44 | +4 |
| Catholic Party | 17,253 | 45.15 | 29 | 94 | –4 |
| Belgian Labour Party | 98 | 0.26 | 0 | 0 | New |
| Others | 30 | 0.08 | 0 | 0 | 0 |
| Total | 38,210 | 100.00 | 69 | 138 | 0 |
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| Total votes | 38,210 | – | |
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| Registered voters/turnout | 59,452 | 64.27 | |
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| Source: Mackie & Rose,[4] Sternberger et al. |
Constituencies
The distribution of seats among the electoral districts was as follows:[5]
References