1866 Belgian general election|
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First party
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Second party
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| Leader
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Charles Rogier
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| Party
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Liberal
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Catholic
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| Leader since
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Candidate for PM
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| Seats before
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64 seats
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52 seats
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| Seats won
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43
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18
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| Seats after
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70
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52
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| Seat change
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6
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| Popular vote
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20,965
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15,060
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| Percentage
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58.20%
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41.80%
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Partial general elections were held in Belgium on 12 June 1866.[1][2] In the elections for the Chamber of Representatives the result was a victory for the Liberal Party, which won 70 of the 122 seats.[2] Voter turnout was 70%, although only 51,465 people were eligible to vote.
Under the alternating system, elections were only held in four out of the nine provinces: Hainaut, Limburg, Liège and East Flanders. Special elections were held in the arrondissements of Antwerp, Brussels and Leuven.
Results
Chamber of Representatives
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| Party | Votes | % | Seats |
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| Won | Total | +/– |
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| Liberal Party | 20,965 | 58.20 | 43 | 70 | +6 |
| Catholics | 15,060 | 41.80 | 18 | 52 | 0 |
| Total | 36,025 | 100.00 | 61 | 122 | +6 |
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| Total votes | 36,025 | – | |
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| Registered voters/turnout | 51,465 | 70.00 | |
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| Source: Mackie & Rose,[3] Sternberger et al. |
Constituencies
The distribution of seats among the electoral districts was as follows for the Chamber of Representatives, with the difference compared to the previous election due to population growth:[4]
References
- ^ Codebook Constituency-level Elections Archive, 2003
- ^ a b Sternberger, D, Vogel, B & Nohlen, D (1969) Die Wahl der Parlamente: Band I: Europa - Erster Halbband, p105
- ^ Thomas T. Mackie & Richard Rose (1991) The International Almanac of Electoral History, Macmillan, pp48–49
- ^ List of members of the Chamber of Representatives (1866-1967)