1836 United States presidential election in Kentucky
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County Results
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| Elections in Kentucky |
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| Government |
A presidential election was held in Kentucky from November 7–9, 1836 as part of the 1836 United States presidential election.[1] Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.
Kentucky voted for Whig candidate William Henry Harrison over the Democratic candidate, Martin Van Buren. Harrison won Kentucky by a margin of 5.18%.
Results
| United States presidential election in Kentucky, 1836[2] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Whig | William Henry Harrison | 36,861 | 52.59% | 15 | |
| Democratic | Martin Van Buren | 33,229 | 47.41% | 0 | |
| Totals | 70,090 | 100.0% | 15 | ||
References
- ^ "Presidential Elections". Weekly Messenger. November 12, 1836.
- ^ "1836 Presidential General Election Results - Kentucky". U.S. Election Atlas. Retrieved August 4, 2012.