A presidential election was held in Arkansas on November 7, 1836 as part of the 1836 United States presidential election.[1] Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.
Arkansas, having been admitted to the Union as the 25th state on June 15, 1836, voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White during its first presidential election. Van Buren won Arkansas by a margin of 28.16%.
Results
Results By County
1836 United States Presidential Election in Arkansas (By County)[3]
| County
|
Martin Van Buren
Democratic
|
Hugh Lawson White
Whig
|
Total
|
| #
|
%
|
#
|
%
|
| Arkansas
|
38
|
31.67%
|
82
|
68.33%
|
120
|
| Carroll
|
73
|
92.41%
|
6
|
7.59%
|
79
|
| Chicot
|
43
|
45.74%
|
51
|
54.26%
|
94
|
| Clark
|
41
|
85.42%
|
7
|
14.58%
|
48
|
| Conway
|
23
|
32.39%
|
48
|
67.61%
|
71
|
| Crawford
|
109
|
47.81%
|
119
|
52.19%
|
228
|
| Crittenden
|
38
|
58.46%
|
27
|
41.54%
|
65
|
| Hempstead
|
110
|
56.99%
|
83
|
43.01%
|
193
|
| Hot Spring
|
11
|
68.75%
|
5
|
31.25%
|
16
|
| Independence
|
134
|
54.25%
|
113
|
45.75%
|
247
|
| Izard
|
87
|
85.29%
|
15
|
14.71%
|
102
|
| Jackson
|
56
|
53.85%
|
48
|
46.15%
|
104
|
| Jefferson
|
50
|
51.02%
|
48
|
48.98%
|
98
|
| Johnson
|
107
|
72.79%
|
40
|
27.21%
|
147
|
| Lafayette
|
30
|
73.17%
|
11
|
26.83%
|
41
|
| Lawrence
|
82
|
72.57%
|
31
|
27.43%
|
113
|
| Monroe
|
17
|
32.69%
|
35
|
67.31%
|
52
|
| Phillips
|
96
|
59.63%
|
65
|
40.37%
|
161
|
| Pike
|
33
|
100.00%
|
0
|
0.00%
|
33
|
| Pope
|
93
|
66.91%
|
46
|
33.09%
|
139
|
| Pulaski
|
234
|
55.06%
|
191
|
44.94%
|
425
|
| Randolph
|
138
|
89.03%
|
17
|
10.97%
|
155
|
| Saline
|
81
|
60.90%
|
52
|
39.10%
|
133
|
| Sevier
|
67
|
66.34%
|
34
|
33.66%
|
101
|
| St. Francis
|
108
|
85.71%
|
18
|
14.29%
|
126
|
| Van Buren
|
19
|
67.86%
|
9
|
32.14%
|
28
|
| Washington
|
622
|
82.38%
|
133
|
17.62%
|
755
|
| White
|
17
|
36.96%
|
29
|
63.04%
|
46
|
| Totals
|
2,380
|
64.08%
|
1,334
|
35.92%
|
3,714
|
See also
References