In mathematical analysis, a bump function (also called a test function) is a function
on a Euclidean space
which is both smooth (in the sense of having continuous derivatives of all orders) and compactly supported. The set of all bump functions with domain
forms a vector space, denoted
or
The dual space of this space endowed with a suitable topology is the space of distributions.
Examples
The function
given by
is an example of a bump function in one dimension. Note that the support of this function is the closed interval
. In fact, by definition of support, we have that
, where the closure is taken with respect the Euclidean topology of the real line. The proof of smoothness follows along the same lines as for the related function discussed in the Non-analytic smooth function article. This function can be interpreted as the Gaussian function
scaled to fit into the unit disc: the substitution
corresponds to sending
to
A simple example of a (square) bump function in
variables is obtained by taking the product of
copies of the above bump function in one variable, so
A radially symmetric bump function in
variables can be formed by taking the function
defined by
. This function is supported on the unit ball centered at the origin.
For another example, take an
that is positive on
and zero elsewhere, for example
.
Smooth transition functions
Consider the function

defined for every real number x.
The function

has a strictly positive denominator everywhere on the real line, hence g is also smooth. Furthermore, g(x) = 0 for x ≤ 0 and g(x) = 1 for x ≥ 1, hence it provides a smooth transition from the level 0 to the level 1 in the unit interval [0, 1]. To have the smooth transition in the real interval [a, b] with a < b, consider the function

For real numbers a < b < c < d, the smooth function

equals 1 on the closed interval [b, c] and vanishes outside the open interval (a, d), hence it can serve as a bump function.
Caution must be taken since, as example, taking
, leads to:

which is not an infinitely differentiable function (so, is not "smooth"), so the constraints a < b < c < d must be strictly fulfilled.
Some interesting facts about the function:

Are that
make smooth transition curves with "almost" constant slope edges (a bump function with true straight slopes is portrayed this Another example).
A proper example of a smooth Bump function would be:

A proper example of a smooth transition function will be:

where could be noticed that it can be represented also through Hyperbolic functions:

Existence of bump functions
It is possible to construct bump functions "to specifications". Stated formally, if
is an arbitrary compact set in
dimensions and
is an open set containing
there exists a bump function
which is
on
and
outside of
Since
can be taken to be a very small neighborhood of
this amounts to being able to construct a function that is
on
and falls off rapidly to
outside of
while still being smooth.
Bump functions defined in terms of convolution
The construction proceeds as follows. One considers a compact neighborhood
of
contained in
so
The characteristic function
of
will be equal to
on
and
outside of
so in particular, it will be
on
and
outside of
This function is not smooth however. The key idea is to smooth
a bit, by taking the convolution of
with a mollifier. The latter is just a bump function with a very small support and whose integral is
Such a mollifier can be obtained, for example, by taking the bump function
from the previous section and performing appropriate scalings.
Bump functions defined in terms of a function
with support
An alternative construction that does not involve convolution is now detailed.
It begins by constructing a smooth function
that is positive on a given open subset
and vanishes off of
This function's support is equal to the closure
of
in
so if
is compact, then
is a bump function.
Start with any smooth function
that vanishes on the negative reals and is positive on the positive reals (that is,
on
and
on
where continuity from the left necessitates
); an example of such a function is
for
and
otherwise.
Fix an open subset
of
and denote the usual Euclidean norm by
(so
is endowed with the usual Euclidean metric).
The following construction defines a smooth function
that is positive on
and vanishes outside of
So in particular, if
is relatively compact then this function
will be a bump function.
If
then let
while if
then let
; so assume
is neither of these. Let
be an open cover of
by open balls where the open ball
has radius
and center
Then the map
defined by
is a smooth function that is positive on
and vanishes off of
For every
let
where this supremum is not equal to
(so
is a non-negative real number) because
the partial derivatives all vanish (equal
) at any
outside of
while on the compact set
the values of each of the (finitely many) partial derivatives are (uniformly) bounded above by some non-negative real number.[note 1]
The series
converges uniformly on
to a smooth function
that is positive on
and vanishes off of
Moreover, for any non-negative integers
where this series also converges uniformly on
(because whenever
then the
th term's absolute value is
). This completes the construction.
As a corollary, given two disjoint closed subsets
of
the above construction guarantees the existence of smooth non-negative functions
such that for any
if and only if
and similarly,
if and only if
then the function
is smooth and for any
if and only if
if and only if
and
if and only if
In particular,
if and only if
so if in addition
is relatively compact in
(where
implies
) then
will be a smooth bump function with support in
Properties and uses
While bump functions are smooth, the identity theorem prohibits their being analytic unless they vanish identically. Bump functions are often used as mollifiers, as smooth cutoff functions, and to form smooth partitions of unity. They are the most common class of test functions used in analysis. The space of bump functions is closed under many operations. For instance, the sum, product, or convolution of two bump functions is again a bump function, and any differential operator with smooth coefficients, when applied to a bump function, will produce another bump function.
If the boundaries of the Bump function domain is
to fulfill the requirement of "smoothness", it has to preserve the continuity of all its derivatives, which leads to the following requirement at the boundaries of its domain:
The Fourier transform of a bump function is a (real) analytic function, and it can be extended to the whole complex plane: hence it cannot be compactly supported unless it is zero, since the only entire analytic bump function is the zero function (see Paley–Wiener theorem and Liouville's theorem). Because the bump function is infinitely differentiable, its Fourier transform must decay faster than any finite power of
for a large angular frequency
[2] The Fourier transform of the particular bump function
from above can be analyzed by a saddle-point method, and decays asymptotically as
for large
[3]
See also
Citations
- ^ The partial derivatives
are continuous functions so the image of the compact subset
is a compact subset of
The supremum is over all non-negative integers
where because
and
are fixed, this supremum is taken over only finitely many partial derivatives, which is why
References