2020 Cleveland Open – Doubles

Doubles
2020 Cleveland Open
Champions Treat Huey
Nathaniel Lammons
Runners-up Luke Saville
John-Patrick Smith
Score7–5, 6–2

Romain Arneodo and Andrei Vasilevski were the defending champions[1] but chose not to defend their title.

Treat Huey and Nathaniel Lammons won the title after defeating Luke Saville and John-Patrick Smith 7–5, 6–2 in the final.

Seeds

Draw

Key

First round Quarterfinals Semifinals Final
1 L Saville
J-P Smith
77 6
WC C Harrison
R Harrison
64 3 1 L Saville
J-P Smith
6 6
S Ofner
R Quiroz
4 2 J Cerretani
M Cressy
4 4
J Cerretani
M Cressy
6 6 1 L Saville
J-P Smith
66 6 [10]
3 LD Martínez
MÁ Reyes-Varela
68 5 L Glasspool
A Lawson
78 4 [6]
R Cid Subervi
S Mansouri
710 7 R Cid Subervi
S Mansouri
3 68
L Glasspool
A Lawson
6 6 L Glasspool
A Lawson
6 710
R Gonzales
R Roelofse
3 4 1 L Saville
J-P Smith
5 2
D Popko
A Tabilo
4 5 T Huey
N Lammons
7 6
T Huey
N Lammons
6 7 T Huey
N Lammons
710 6
WC Ian Dempster
K Lovett
6 4 [10] WC I Dempster
K Lovett
68 4
4 D Novikov
G Oliveira
4 6 [8] T Huey
N Lammons
6 77
N Pasha
Ma Redlicki
2 1 R Galloway
H Hach Verdugo
3 65
R Galloway
H Hach Verdugo
6 6 R Galloway
H Hach Verdugo
6 710
WC James Hopper
Nico Mostardi
4 4 2 J-s Nam
M-k Song
3 68
2 J-s Nam
M-k Song
6 6

References

  1. ^ "Cleveland Open is returning to Cleveland Racquet Club in February". Crain's Cleveland Business. September 20, 2019.