2019 Sarasota Open – Doubles

Doubles
2019 Sarasota Open
Champions Martín Cuevas
Paolo Lorenzi
Runners-up Luke Bambridge
Jonny O'Mara
Score7–6(7–5), 7–6(8–6)

Evan King and Hunter Reese were the defending champions[1] but only Reese chose to defend his title, partnering André Göransson. Reese lost in the first round to Treat Huey and Fabrice Martin.

Martín Cuevas and Paolo Lorenzi won the title after defeating Luke Bambridge and Jonny O'Mara 7–6(7–5), 7–6(8–6) in the final.

Seeds

Draw

Key

First round Quarterfinals Semifinals Final
1 L Bambridge
J O'Mara
6 3 [10]
T Sandgren
J Ward
2 6 [6] 1 L Bambridge
J O'Mara
6 6
A Lawson
P Polansky
77 6 A Lawson
P Polansky
3 3
ITF S Ehrat
A Zhurbin
62 2 1 L Bambridge
J O'Mara
6 6
3 N Lammons
A-u-H Qureshi
77 6 3 N Lammons
A-u-H Qureshi
4 2
WC JC Aragone
M Giron
65 4 3 N Lammons
A-u-H Qureshi
64 6 [10]
A Göransson
H Reese
6 3 [5] PR T Huey
F Martin
77 4 [8]
PR T Huey
F Martin
4 6 [10] 1 L Bambridge
J O'Mara
65 66
H Heliövaara
H Laaksonen
M Cuevas
P Lorenzi
77 78
M Cuevas
P Lorenzi
w/o M Cuevas
P Lorenzi
65 7 [10]
ITF A Rinderknech
D Yevseyev
62 77 [7] 4 R Maytín
F Romboli
77 5 [7]
4 R Maytín
F Romboli
77 63 [10] M Cuevas
P Lorenzi
6 77
M Krueger
M Reid
7 77 WC B Arias
S Bangoura
4 63
WC Russell Berdusco
Micah Braswell
5 62 M Krueger
M Reid
4 4
WC B Arias
S Bangoura
5 7 [10] WC B Arias
S Bangoura
6 6
2 J Nedunchezhiyan
P Raja
7 5 [5]

References

  1. ^ Brockman, Jim. "TENNIS: Dellien rallies to win Sarasota Open". Sarasota Herald-Tribune.