2019 Lale Cup – Doubles

Doubles
2019 Lale Cup
Champions Marie Bouzková
Rosalie van der Hoek
Runners-up Ilona Kremen
Iryna Shymanovich
Score7–5, 6–7(2–7), [10–5]

Ayla Aksu and Harriet Dart were the defending champions, but both players chose not to participate.

Marie Bouzková and Rosalie van der Hoek won the title, defeating Ilona Kremen and Iryna Shymanovich in the final, 7–5, 6–7(2–7), [10–5].[1]

Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 O Doroshina
P Monova
  Ç Büyükakçay
A Vrljić
w/o Ç Büyükakçay
A Vrljić
  G Poznikhirenko
S Sharipova
7 4 [8] M Bouzková
R van der Hoek
w/o
  M Bouzková
R van der Hoek
5 6 [10] M Bouzková
R van der Hoek
7 7
3 B Cengiz
J Rompies
6 6 3 B Cengiz
J Rompies
5 5
WC Z Erman
Z Sönmez
3 4 3 B Cengiz
J Rompies
1 6 [11]
  İ Soylu
B Štefková
6 6 İ Soylu
B Štefková
6 4 [9]
WC İ Öz
M Sezer
3 3 M Bouzková
R van der Hoek
7 62 [10]
  I Kremen
I Shymanovich
6 6 I Kremen
I Shymanovich
5 77 [5]
  Á Bukta
V Juhászová
2 3 I Kremen
I Shymanovich
4 6 [11]
  G Minnen
P Özgen
7 6 G Minnen
P Özgen
6 3 [9]
4 V Grammatikopoulou
A Raina
5 4 I Kremen
I Shymanovich
66 6 [11]
  A Gasanova
J Terziyska
6 77 2 R Șerban
I Shinikova
78 3 [9]
  F Al-Nabhani
C Anıl
1 63 A Gasanova
J Terziyska
6 62 [7]
WC L Aiche
BE Gümüşsoy
0 0 2 R Șerban
I Shinikova
4 77 [10]
2 R Șerban
I Shinikova
6 6

References

  1. ^ "W60 Istanbul". www.itftennis.com.