2019 Internazionali di Tennis d'Abruzzo – Doubles

Doubles
2019 Internazionali di Tennis d'Abruzzo
Champions Denys Molchanov
Igor Zelenay
Runners-up Guillermo Durán
David Vega Hernández
Score6–3, 6–2

Julian Ocleppo and Andrea Vavassori were the defending champions[1] but lost in the first round to Jonathan Eysseric and Andrei Vasilevski.

Denys Molchanov and Igor Zelenay won the title after defeating Guillermo Durán and David Vega Hernández 6–3, 6–2 in the final.

Seeds

Draw

Key

First round Quarterfinals Semifinals Final
1 D Molchanov
I Zelenay
6 6
K Coppejans
S Gillé
6 65 [9] E Couacaud
R Molleker
3 3
E Couacaud
R Molleker
4 77 [11] 1 D Molchanov
I Zelenay
6 6
3 P Oswald
F Polášek
w/o 3 P Oswald
F Polášek
3 1
ITF R Bonadio
D Pérez Sanz
3 P Oswald
F Polášek
6 6
WC Andrea Del Federico
S Travaglia
w/o WC A Del Federico
S Travaglia
3 3
Q Halys
G Sakharov
1 D Molchanov
I Zelenay
6 6
WC Alessio De Bernardis
Giuseppe Tresca
2 1 2 G Durán
D Vega Hernández
3 2
T Brkić
N Čačić
6 6 T Brkić
N Čačić
6 77
J Ocleppo
A Vavassori
6 3 [5] 4 J Eysseric
A Vasilevski
4 63
4 J Eysseric
A Vasilevski
3 6 [10] T Brkić
N Čačić
3 64
ITF J Barranco Cosano
R Brancaccio
4 1 2 G Durán
D Vega Hernández
6 77
WC L Musetti
G Zeppieri
6 0r ITF J Barranco Cosano
R Brancaccio
3 1r
V Galović
A Pellegrino
0 6 [9] 2 G Durán
D Vega Hernández
6 4
2 G Durán
D Vega Hernández
6 4 [11]

References

  1. ^ "Internazionali Tennis: doppio alla coppia italiana Ocleppo - Vavassori". 28 April 2018.