2019 Canberra Challenger – Doubles
| Doubles | |
|---|---|
| 2019 Canberra Challenger | |
| Champions | Marcelo Demoliner Hugo Nys |
| Runners-up | André Göransson Sem Verbeek |
| Score | 3–6, 6–4, [10–3] |
Jonathan Erlich and Divij Sharan were the defending champions but chose not to defend their title.
Marcelo Demoliner and Hugo Nys won the title after defeating André Göransson and Sem Verbeek 3–6, 6–4, [10–3] in the final.[1]
Seeds
- Denys Molchanov / Igor Zelenay (semifinals)
- Andreas Mies / Hans Podlipnik Castillo (quarterfinals)
- Marcelo Demoliner / Hugo Nys (champions)
- David Marrero / Fabrice Martin (first round)
Draw
Key
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- ITF = ITF entry
- PR = Protected ranking
- SR = Special ranking
- SE = Special exempt
- JE = Junior exempt
- JR = Junior Accelerator Programme entrant
- CO = College Accelerator Programme entrant
- NG = Next Gen Accelerator Program entrant
- w/o = Walkover
- r = Retired
- d = Defaulted
| First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
| 1 | D Molchanov I Zelenay | 3 | 6 | [10] | |||||||||||||||||||||||
| B Klein B Mousley | 6 | 3 | [7] | 1 | D Molchanov I Zelenay | 77 | 6 | ||||||||||||||||||||
| WC | H Bourchier D Kelly | 6 | 1 | [8] | A Harris Z Li | 63 | 3 | ||||||||||||||||||||
| A Harris Z Li | 2 | 6 | [10] | 1 | D Molchanov I Zelenay | 5 | 6 | [8] | |||||||||||||||||||
| 3 | M Demoliner H Nys | 6 | 77 | 3 | M Demoliner H Nys | 7 | 3 | [10] | |||||||||||||||||||
| S Gillé J Vliegen | 3 | 64 | 3 | M Demoliner H Nys | 65 | 6 | [11] | ||||||||||||||||||||
| WC | A Taylor J Taylor | 4 | 4 | JP Fruttero M-A Hüsler | 77 | 4 | [9] | ||||||||||||||||||||
| JP Fruttero M-A Hüsler | 6 | 6 | 3 | M Demoliner H Nys | 3 | 6 | [10] | ||||||||||||||||||||
| A Göransson S Verbeek | 6 | 6 | A Göransson S Verbeek | 6 | 4 | [3] | |||||||||||||||||||||
| WC | T Fancutt Jacob Grills | 3 | 2 | A Göransson S Verbeek | 6 | 6 | |||||||||||||||||||||
| T Brkić R Olivo | 5 | 6 | [10] | T Brkić R Olivo | 4 | 2 | |||||||||||||||||||||
| 4 | D Marrero F Martin | 7 | 2 | [6] | A Göransson S Verbeek | 6 | 7 | ||||||||||||||||||||
| A Behar G Blancaneaux | 6 | 6 | A Behar G Blancaneaux | 1 | 5 | ||||||||||||||||||||||
| ITF | S Doumbia A Zhurbin | 2 | 2 | A Behar G Blancaneaux | 4 | 6 | [15] | ||||||||||||||||||||
| ITF | M Bortolotti S Puodziunas | 3 | 3 | 2 | A Mies H Podlipnik Castillo | 6 | 2 | [13] | |||||||||||||||||||
| 2 | A Mies H Podlipnik Castillo | 6 | 6 | ||||||||||||||||||||||||
References
- ^ Tiernan, Eamonn (12 January 2019). "Hurkacz wins Canberra Challenger and now faces tall task in Melbourne". Canberra Times.