2019 Berkeley Tennis Club Challenge – Doubles

Doubles
2019 Berkeley Tennis Club Challenge
Champions Madison Brengle
Sachia Vickery
Runners-up Francesca Di Lorenzo
Katie Swan
Score6–3, 7–5

Nicole Gibbs and Asia Muhammad were the defending champions, but both players chose not to participate.[1]

Madison Brengle and Sachia Vickery won the title, defeating Francesca Di Lorenzo and Katie Swan in the final, 6–3, 7–5.

Seeds

  1. Giuliana Olmos / Luisa Stefani (semifinals)
  2. Hsieh Yu-chieh / You Xiaodi (quarterfinals)
  3. Han Na-lae / Hiroko Kuwata (quarterfinals)
  4. Chen Pei-hsuan / Wu Fang-hsien (quarterfinals)

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 G Olmos
L Stefani
6 6
  L Cabrera
Z Hives
3 4 1 G Olmos
L Stefani
6 6
  J Namigata
M Yonehara
6 6 J Namigata
M Yonehara
1 1
Alt F Al-Nabhani
D-b Kim
3 3 1 G Olmos
L Stefani
3 77 [9]
3 N-l Han
H Kuwata
6 6 F Di Lorenzo
K Swan
6 62 [11]
  H Arakawa
A Shimizu
4 4 3 N-l Han
H Kuwata
65 3
  F Di Lorenzo
K Swan
6 6 F Di Lorenzo
K Swan
77 6
  B Boren
G Brodsky
3 4 F Di Lorenzo
K Swan
3 5
  K Ahn
C Harrison
77 6 M Brengle
S Vickery
6 7
  D Khazaniuk
C Simmonds
64 4 K Ahn
C Harrison
77 6
WC M Thiel
C Van Nguyen
2 4 4 P-h Chen
F-h Wu
63 0
4 P-h Chen
F-h Wu
6 6 K Ahn
C Harrison
1 0
  M Brengle
S Vickery
65 6 [10] M Brengle
S Vickery
6 6
WC A Zamarripa
M Zamarripa
77 2 [5] M Brengle
S Vickery
6 7
  S Marand
T Moore
4 1 2 Y-c Hsieh
X You
0 5
2 Y-c Hsieh
X You
6 6

References

  1. ^ "W60 Berkeley". www.itftennis.com.