2019 BNP Paribas Primrose Bordeaux – Doubles

Doubles
2019 BNP Paribas Primrose Bordeaux
Champions Grégoire Barrère
Quentin Halys
Runners-up Romain Arneodo
Hugo Nys
Score6–4, 6–1

Bradley Klahn and Peter Polansky were the defending champions but chose not to defend their title.[1]

Grégoire Barrère and Quentin Halys won the title after defeating Romain Arneodo and Hugo Nys 6–4, 6–1 in the final.

Seeds

  1. Nicolas Mahut / Jürgen Melzer (quarterfinals, retired)
  2. James Cerretani / Nicholas Monroe (quarterfinals)
  3. Gong Maoxin / Zhang Ze (semifinals)
  4. Sander Gillé / David Vega Hernández (quarterfinals)

Draw

Key

First round Quarterfinals Semifinals Final
1 N Mahut
J Melzer
64 6 [10]
G Mager
A Pellegrino
77 4 [8] 1 N Mahut
J Melzer
63 2
WC E Benchetrit
T Lamasine
6 6 WC E Benchetrit
T Lamasine
77 1r
D Gimeno Traver
D Marrero
3 2 WC E Benchetrit
T Lamasine
3 1
4 S Gillé
D Vega Hernández
6 6 R Arneodo
H Nys
6 6
WC G Jacq
A Olivetti
4 2 4 S Gillé
D Vega Hernández
62 6 [4]
R Arneodo
H Nys
6 77 R Arneodo
H Nys
77 4 [10]
J Eysseric
A Šančić
3 63 R Arneodo
H Nys
4 1
E Ymer
M Ymer
2 6 [10] G Barrère
Q Halys
6 6
ITF R Brancaccio
K-M Maamoun
6 3 [6] E Ymer
M Ymer
2 4
ITF S Martos Gornés
O Roca Batalla
3 77 [6] 3 M Gong
Ze Zhang
6 6
3 M Gong
Ze Zhang
6 64 [10] 3 M Gong
Ze Zhang
4 3
K Coppejans
Z Kolář
66 4 G Barrère
Q Halys
6 6
G Barrère
Q Halys
78 6 G Barrère
Q Halys
7 6
WC Joffrey de Schepper
K de Schepper
2 3 2 J Cerretani
N Monroe
5 4
2 J Cerretani
N Monroe
6 6

References

  1. ^ "Florida's Opelka Wins $100K Bordeaux Challenger Title". 21 May 2018.