2018 Sopot Open – Doubles

Doubles
2018 Sopot Open
Champions Mateusz Kowalczyk
Szymon Walków
Runners-up Ruben Gonzales
Nathaniel Lammons
Score7–6(8–6), 6–3[1]

This was the first edition of the tournament.[2]

Mateusz Kowalczyk and Szymon Walków won the title after defeating Ruben Gonzales and Nathaniel Lammons 7–6(8–6), 6–3 in the final.[1]

Seeds

Draw

Key

First round Quarterfinals Semifinals Final
1 A Bury
A Mies
6 1 [8]
D Propoggia
S Puodziunas
2 6 [10] D Propoggia
S Puodziunas
2 4
WC K Majchrzak
J Zieliński
2 64 M Kowalczyk
S Walków
6 6
M Kowalczyk
S Walków
6 77 M Kowalczyk
S Walków
77 7
3 F Agamenone
V Manafov
6 66 [13] G Panfil
G Sakharov
62 5
WC Paweł Ciaś
Michał Dembek
3 78 [11] 3 F Agamenone
V Manafov
4 4
Alt J Choinski
J Härteis
3 2 G Panfil
G Sakharov
6 6
G Panfil
G Sakharov
6 6 M Kowalczyk
S Walków
78 6
A Collarini
M Zekić
6 6 2 R Gonzales
N Lammons
66 3
Z Kolář
A Motti
4 4 A Collarini
M Zekić
2 4
M Cuevas
H Dellien
3 6 [10] M Cuevas
H Dellien
6 6
4 T Bednarek
V Uzhylovskyi
6 3 [7] M Cuevas
H Dellien
V Orlov
A Smirnov
4 6 [6] 2 R Gonzales
N Lammons
w/o
WC K Drzewiecki
K Żuk
6 3 [10] WC K Drzewiecki
K Żuk
3 1
P Cachin
R Olivo
4 2 2 R Gonzales
N Lammons
6 6
2 R Gonzales
N Lammons
6 6

References

  1. ^ a b Szadurski, Szymon (August 5, 2019). "Sopot Open 2018. Włoskie zwycięstwo na kortach w Gdyni". Dziennik Bałtycki (in Polish). Retrieved July 19, 2019.
  2. ^ Ilic, Jovica (May 31, 2018). "Jerzy Janowicz and Tommy Robredo lead inaugural Sopot Open field". worldtennisusa.org. Retrieved July 19, 2019.

Sources