2018 Brisbane International – Men's doubles

Men's doubles
2018 Brisbane International
Champions Henri Kontinen
John Peers
Runners-up Leonardo Mayer
Horacio Zeballos
Score3–6, 6–3, [10–2]

Thanasi Kokkinakis and Jordan Thompson were the defending champions, but Kokkinakis chose to compete in the Hopman Cup instead. Thompson played alongside Lleyton Hewitt, but lost in the first round to Grigor Dimitrov and Ryan Harrison.

Henri Kontinen and John Peers won the title, defeating Leonardo Mayer and Horacio Zeballos in the final, 3–6, 6–3, [10–2].

Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 H Kontinen
J Peers
77 6
M Raonic
D Shapovalov
63 4 1 H Kontinen
J Peers
6 6
PR I Bozoljac
D Džumhur
1 2 PR M Ebden
J Millman
4 3
PR M Ebden
J Millman
6 6 1 H Kontinen
J Peers
w/o
4 M Daniell
D Inglot
6 1 [7] G Dimitrov
R Harrison
N Kyrgios
M Reid
4 6 [10] N Kyrgios
M Reid
62 63
WC L Hewitt
J Thompson
3 6 [5] G Dimitrov
R Harrison
77 77
G Dimitrov
R Harrison
6 1 [10] 1 H Kontinen
J Peers
3 6 [10]
W Koolhof
A Sitak
6 6 L Mayer
H Zeballos
6 3 [2]
T Huey
F Martin
3 2 W Koolhof
A Sitak
78 7
S Johnson
G Müller
77 4 [11] S Johnson
G Müller
66 5
3 S González
J Peralta
62 6 [9] W Koolhof
A Sitak
6 1 [6]
D Schwartzman
M Zverev
2 0 L Mayer
H Zeballos
4 6 [10]
L Mayer
H Zeballos
6 6 L Mayer
H Zeballos
77 65 [13]
N Monroe
J-P Smith
6 3 [5] 2 M Demoliner
M Venus
61 77 [11]
2 M Demoliner
M Venus
4 6 [10]

References