2018 Boyd Tinsley Clay Court Classic – Doubles

Doubles
2018 Boyd Tinsley Clay Court Classic
Champions Sophie Chang
Alexandra Mueller
Runners-up Ashley Kratzer
Whitney Osuigwe
Score3–6, 6–4, [10–7]
Main article: 2018 Boyd Tinsley Clay Court Classic

Jovana Jakšić and Catalina Pella were the defending champions, but decided not to participate.

Sophie Chang and Alexandra Mueller won the title after defeating Ashley Kratzer and Whitney Osuigwe 3–6, 6–4, [10–7] in the final.

Seeds

  1. Irina Bara / Mariana Duque Mariño (semifinals)
  2. Alexa Guarachi / Erin Routliffe (quarterfinals)
  3. Sophie Chang / Alexandra Mueller (champions)
  4. Paula Cristina Gonçalves / Sanaz Marand (first round)

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 I Bara
M Duque Mariño 		6 6
  K Cartwright
K Pierre-Louis 		3 1 1 I Bara
M Duque Mariño 		2 7 [10]
WC A Smith
N Subhash 		6 6 WC A Smith
N Subhash 		6 5 [5]
  M Mateas
R Yurovsky 		2 4 1 I Bara
M Duque Mariño 		6 4 [4]
3 S Chang
A Mueller 		6 6 3 S Chang
A Mueller 		1 6 [10]
  L Chirico
F Di Lorenzo 		3 3 3 S Chang
A Mueller 		7 6
  P Januskova
R Ozaki 		4 6 [7] C Rosatello
AS Sánchez 		5 2
  C Rosatello
AS Sánchez 		6 3 [10] 3 S Chang
A Mueller 		3 6 [10]
  V Duval
J Loeb 		6 4 [10] A Kratzer
W Osuigwe 		6 4 [7]
  Q Gleason
A Weinhold 		2 6 [8] V Duval
J Loeb 		6 62 [10]
  A Kratzer
W Osuigwe 		6 6 A Kratzer
W Osuigwe 		3 77 [12]
4 PC Gonçalves
S Marand 		3 4 A Kratzer
W Osuigwe 		6 2 [12]
  J Cristian
K Day 		1 3 I Neel
M Sanchez 		4 6 [10]
  I Neel
M Sanchez 		6 6 I Neel
M Sanchez 		6 1 [20]
  R McAdoo
K Stewart 		6 4 [7] 2 A Guarachi
E Routliffe 		2 6 [18]
2 A Guarachi
E Routliffe 		2 6 [10]

References

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