1999 ATP Tour World Championships – Doubles

Doubles
1999 ATP Tour World Championships
Champions Sébastien Lareau
Alex O'Brien
Runners-up Mahesh Bhupathi
Leander Paes
Score6–3, 6–2, 6–2
Draw8

Sébastien Lareau and Alex O'Brien defeated Mahesh Bhupathi and Leander Paes in the final, 6–3, 6–2, 6–2 to win the doubles tennis title at the 1999 ATP Tour World Championships.[1]

Jacco Eltingh and Paul Haarhuis were the reigning champions, but did not compete together in 1999. Eltingh retired from the sport on November 22, 1998; Haarhuis qualified with Jared Palmer, but was eliminated in the round-robin stage.

Seeds

  1. Mahesh Bhupathi / Leander Paes (final)
  2. Todd Woodbridge / Mark Woodforde (semifinals)
  3. Ellis Ferreira / Rick Leach (round robin)
  4. Sébastien Lareau / Alex O'Brien (champions)
  5. David Adams / John-Laffnie de Jager (round robin, withdrew due to a flu of de Jager)
  6. Wayne Black / Sandon Stolle (semifinals)
  7. Paul Haarhuis / Jared Palmer (round robin)
  8. Piet Norval / Kevin Ullyett (round robin)
  9. Jiří Novák / David Rikl (round robin)

Draw

Key

Finals

Semifinals Final
            
1 Mahesh Bhupathi
Leander Paes
5 6 7
2 Todd Woodbridge
Mark Woodforde
7 2 5
1 Mahesh Bhupathi
Leander Paes
3 2 2    
4 Sébastien Lareau
Alex O'Brien
6 6 6    
4 Sébastien Lareau
Alex O'Brien
6 7  
6 Wayne Black
Sandon Stolle
3 5  

Gold group

  Bhupathi
Paes
Ferreira
Leach
Black
Stolle
Norval
Ullyett
RR
W–L
Set
W–L
Game
W–L
Standings
1 Mahesh Bhupathi
Leander Paes
6–4, 6–4 7–6(7–5), 5–7, 2–6 7–6(7–1), 6–3 2–1 5–2 39–36 2
3 Ellis Ferreira
Rick Leach
4–6, 4–6 6–3, 6–2 3–6, 3–6 1–2 2–4 26–29 4
6 Wayne Black
Sandon Stolle
6–7(5–7), 7–5, 6–2 3–6, 2–6 7–6(7–5), 6–1 2–1 4–3 37–33 1
8 Piet Norval
Kevin Ullyett
6–7(1–7), 3–6 6–3, 6–3 6–7(5–7), 1–6 1–2 2–4 28–32 3

Standings are determined by: 1. number of wins; 2. number of matches; 3. in two-players-ties, head-to-head records; 4. in three-players-ties, percentage of sets won, or of games won; 5. steering-committee decision.

Green group

  Woodbridge
Woodforde
Lareau
O'Brien
Adams
de Jager
Novák
Rikl
Haarhuis
Plamer
RR
W–L
Set
W–L
Game
W–L
Standings
2 Todd Woodbridge
Mark Woodforde
7–6(7–3), 6–4 6–2, 6–4
(w/ Novák / Rikl)
6–4, 6–2 3–0 6–0 37–22 1
4 Sébastien Lareau
Alex O'Brien
6–7(3–7), 4–6 6–2, 7–6(7–5)
(w/ Adams / de Jager)
7–6(7–1), 6–2 2–1 4–2 36–29 2
5
9
David Adams
John-Laffnie de Jager
Jiří Novák
David Rikl
2–6, 4–6
(w/ Novák / Rikl)
2–6, 6–7(5–7)
(w/ Adams / de Jager)
4–6, 5–7
(w/ Adams / de Jager)
0–2
0–1
0–4
0–2
17–26
6–12
4
5
7 Paul Haarhuis
Jared Palmer
4–6, 2–6 6–7(1–7), 2–6 6–4, 7–5
(w/ Adams / de Jager)
1–2 2–4 27–34 3

Standings are determined by: 1. number of wins; 2. number of matches; 3. in two-players-ties, head-to-head records; 4. in three-players-ties, percentage of sets won, or of games won; 5. steering-committee decision.

References

  1. ^ "1999 ATP Tour World Championships – Doubles results". Association of Tennis Professionals (ATP).