1993 Comcast U.S. Indoor – Doubles

Doubles
1993 Comcast U.S. Indoor
Champions Jim Grabb
Richey Reneberg
Runners-up Marcos Ondruska
Brad Pearce
Score6–7, 6–3, 6–0

Todd Woodbridge and Mark Woodforde were the defending champions, but lost in the first round this year.

Jim Grabb and Richey Reneberg won the title, defeating Marcos Ondruska and Brad Pearce 6–7, 6–3, 6–0 in the final.[1]

Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 J Grabb
R Reneberg
6 6  
  B Garnett
M Keil
4 4   1 J Grabb
R Reneberg
6 6  
  J Pugh
G Van Emburgh
6 3 2 WC P Sampras
J Tarango
4 2  
WC P Sampras
J Tarango
4 6 6 1 J Grabb
R Reneberg
6 6  
3 P McEnroe
J Palmer
2 6 6 3 P McEnroe
J Palmer
3 1  
  N Broad
S Kruger
6 1 1 3 P McEnroe
J Palmer
6 6  
  K Kinnear
S Salumaa
6 7     K Kinnear
S Salumaa
1 4  
  M Briggs
T Kronemann
4 6   1 J Grabb
R Reneberg
6 6 6
  S Cannon
S Melville
4 3     M Ondruska
B Pearce
7 3 0
  G Michibata
D Pate
6 6     G Michibata
D Pate
2 3  
Q C Allgårdh
C Limberger
1 6   4 J Eltingh
P Haarhuis
6 6  
4 J Eltingh
P Haarhuis
6 7   4 J Eltingh
P Haarhuis
5 4  
WC B Gilbert
E Sánchez
6 2 3   M Ondruska
B Pearce
7 6  
  K Flach
D Randall
4 6 6   K Flach
D Randall
6 7 5
  M Ondruska
B Pearce
6 7     M Ondruska
B Pearce
7 6 7
2 T Woodbridge
M Woodforde
3 6  

References

  1. ^ John Barrett, ed. (1994). International Tennis Federation World of Tennis 1994. London: CollinsWillow. p. 122. ISBN 9780002184564.