1990 Virginia Slims of Houston – Singles

Singles
1990 Virginia Slims of Houston
Champion Katerina Maleeva
Runner-up Arantxa Sánchez Vicario
Score6–1, 1–6, 6–4
Draw16 (2Q)
Seeds4

Monica Seles was the defending champion but she chose to compete at San Antonio during the same week, winning the title.

Katerina Maleeva won the title by defeating Arantxa Sánchez Vicario 6–1, 1–6, 6–4 in the final.[1][2]

Seeds

  1. Martina Navratilova (semifinals)
  2. Zina Garrison (semifinals)
  3. Arantxa Sánchez Vicario (final)
  4. Katerina Maleeva (champion)

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 M Navratilova 6 6
Q B Fulco 0 1 1 M Navratilova 7 6
A Temesvári 6 6 A Temesvári 5 2
Nicoletta Iaccarino 2 1 1 M Navratilova 4 6 1
4 K Maleeva 711 6 4 K Maleeva 6 2 6
L Meskhi 69 1 4 K Maleeva 6 77
L Gildemeister 6 7 L Gildemeister 2 63
I Cueto 2 5 4 K Maleeva 6 1 6
Q ML Daniels 6 6 3 A Sánchez Vicario 1 6 4
S Hanika 4 4 Q ML Daniels 5 2
G Magers 3 3 3 A Sánchez Vicario 7 6
3 A Sánchez Vicario 6 6 3 A Sánchez Vicario 64 6 79
S Cecchini 3 6 6 2 Z Garrison 77 3 67
S Sloane 6 2 3 S Cecchini 1 3
N Zvereva 6 3 3 2 Z Garrison 6 6
2 Z Garrison 4 6 6

References

  1. ^ "Fourth-seeded Katerina Maleeva of Bulgaria defeated third-seed Arantxa Sanchez..." Houston. United Press International. 1 April 1990. Retrieved 26 June 2025.
  2. ^ "TENNIS ROUNDUP : Chang Finally Gets Break in Victory Over Grabb". Los Angeles Times. Associated Press. 2 April 1990. Retrieved 26 June 2025. Katerina Maleeva of Bulgaria continued her string of upsets, knocking off second-seeded Arantxa Sanchez of Spain, 6-1, 1-6, 6-4, to win a Virginia Slims tournament at Houston.