1989 Virginia Slims of Chicago – Doubles

Doubles
1989 Virginia Slims of Chicago
Champions Larisa Savchenko
Natasha Zvereva
Runners-up Jana Novotná
Helena Suková
Score6–3, 2–6, 6–3
Draw16
Seeds4

Lori McNeil and Betsy Nagelsen were the defending champions, but both players competed this year with different partners. McNeil teamed up with Hana Mandlíková and were forced to withdraw in the quarterfinals, while Nagelsen teamed up with Mary Joe Fernández and lost in the semifinals to Larisa Savchenko and Natasha Zvereva

Savchenko and Zvereva won the title by defeating Jana Novotná and Helena Suková 6–3, 2–6, 6–3 in the final.[1]

Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 J Novotná
H Suková
6 4 6
E Burgin
R Fairbank
3 6 2 1 J Novotná
H Suková
w/o
R Baranski
D Faber
6 4 2 H Mandlíková
L McNeil
H Mandlíková
L McNeil
3 6 6 1 J Novotná
H Suková
7 6
3 K Adams
Z Garrison
6 6 B Schultz
P Shriver
5 1
S Amiach
C Reynolds
4 3 3 K Adams
Z Garrison
5 5
A Frazier
M Werdel
3 0 B Schultz
P Shriver
7 7
B Schultz
P Shriver
6 6 1 J Novotná
H Suková
3 6 3
A Henricksson
A Smith
2 4 2 L Savchenko
N Zvereva
6 2 6
B Bunge
E Pfaff
6 6 B Bunge
E Pfaff
4 1
K Gompert
P Vásquez
3 1 4 MJ Fernández
B Nagelsen
6 6
4 MJ Fernández
B Nagelsen
6 6 4 MJ Fernández
B Nagelsen
2 2
R Casals
J Smoller
1 3 2 L Savchenko
N Zvereva
6 6
M Lindström
H Ludloff
6 6 M Lindström
H Ludloff
6 5 3
G Magers
K Rinaldi
63 1 2 L Savchenko
N Zvereva
4 7 6
2 L Savchenko
N Zvereva
77 6

References

  1. ^ John Barrett, ed. (1990). The International Tennis Federation : World of Tennis 1990. London: Willow Books. pp. 163, 165, 200–201. ISBN 9780002183550.