1988 WTA German Open – Doubles

Doubles
1988 WTA German Open
1987 Champions
Champions
Runners-up
Score6–2, 4–6, 6–4
Draw28
Seeds8

Claudia Kohde-Kilsch and Helena Suková were the defending champions but lost in the final 6–2, 4–6, 6–4 against Isabelle Demongeot and Nathalie Tauziat.[1]

Seeds

Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated. The top four seeded teams received byes into the second round.

Draw

Key

Final

Final
     
1 2 6 4
5 6 4 6

Top half

First round Second round Quarterfinals Semifinals
1 6 6  
  6 6     1 3  
  3 2   1 6 6  
  6 6   6 3 2  
  4 4     5 1  
  2 3   6 7 6  
6 6 6   1 6 6  
8 2 1  
4 6 6  
  6 6     2 2  
  2 4   4 1 7 4
  6 6   8 6 5 6
 
2 1     4 6  
  5 5   8 6 7  
8 7 7  

Bottom half

First round Second round Quarterfinals Semifinals
7 6 6  
  2 4   7 6 4 6
  2 3     3 6 2
  6 6   7 6 2 6
  S Cecchini
S Goleš
0 6 6 3 3 6 3
  6 1 2   S Cecchini
S Goleš
6 4  
3 7 6  
7 4 3  
5 6 4 6 5 6 6  
  0 6 3 5 6 6  
  6 6 6   0 3  
  7 2 4 5 4 6 7
  6 6     6 1 6
  1 4     2 6 7
2 6 2 6

References

  1. ^ John Barrett, ed. (1989). The International Tennis Federation : World of Tennis 1989. London: Willow Books. pp. 174, 194–195. ISBN 9780002183116.