1948 Australian Championships – Women's singles

Women's singles
1948 Australian Championships
Champion Nancye Bolton
Runner-up Marie Toomey
Score6–3, 6–1
Draw28
Seeds8

First-seeded Nancye Bolton defeated Marie Toomey 6–3, 6–1 in the final to win the women's singles tennis title at the 1948 Australian Championships.

Seeds

The seeded players are listed below. Nancye Bolton is the champion; others show the round in which they were eliminated.

  1. Nancye Bolton (champion)
  2. Thelma Long (second round)
  3. Mary Bevis (semifinals)
  4. Marie Toomey (finalist)
  5. Pat Jones (second round)
  6. Nell Hopman (quarterfinals)
  7. Sadie Newcombe (second round)
  8. Dulcie Whittaker (first round)

Draw

Key

Finals

Quarterfinals Semifinals Finals
               
1 Nancye Bolton 6 6
Joan Tuckfield 2 0
1 Nancye Bolton 6 6
3 Mary Beavis 3 4
3 Mary Beavis 7 6
6 Nell Hopman 5 4
1 Nancye Bolton 6 6
4 Marie Toomey 3 1
Dorothy Jenkins 6 3
4 Marie Toomey 8 6
4 Marie Toomey 4 7 6
Esme Ashford 6 5 4
Esme Ashford 6 6
Clare Proctor 1 0

Earlier rounds

Section 1

First round Second round Quarterfinals Semifinals
1 Bolton 6 6
Earle 1 0
1 Bolton 6 6
Martin Tuckfield 2 0
8 Whittaker w/o Martin 5 3
Tuckfield 3 9 6 Tuckfield 7 6
Thiele 6 7 4 1 Bolton 6 6
3 Beavis 6 6 3 Beavis 3 4
Murphy 2 2 3 Beavis 6 6
McDermott 6 6 McDermott 2 4
Linehan 0 0 3 Beavis 7 6
6 Hopman 6 6 6 Hopman 5 4
Schultz 0 0 6 Hopman 6 6
Baker 6 8 Baker 1 3
Taylor 4 6

Section 2

First round Second round Quarterfinals Semifinals
Jenkins 6 6
Radford 3 0 Jenkins 3 6 6
5 Jones 6 6 5 Jones 6 3 4
Jackson 0 2 Jenkins 8 6
Moran 6 6 4 Toomey 6 3
Longton 2 1 Moran w/o
4 Toomey 6 6 4 Toomey
Griffiths 0 0 4 Toomey 4 7 6
Ashford 6 4 6 Ashford 6 5 4
Chamberlin 2 6 2 Ashford 6 4 7
7 Newcombe 6 6 7 Newcombe 0 6 5
Johnston 1 0 Ashford 6 6
Proctor 1 0
Proctor
2 Long w/o

References

  • [1] Source for the draw at ausopen.com
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