1938 Australian Championships – Women's singles

Women's singles
1938 Australian Championships
Champion Dorothy Bundy
Runner-up Dorothy Stevenson
Score6–3, 6–2
Draw24
Seeds8

First-seeded Dorothy Bundy defeated Dorothy Stevenson 6–3, 6–2, in the final to win the women's singles tennis title at the 1938 Australian Championships.[1]

Seeds

The seeded players are listed below. Dorothy Bundy is the champion; others show the round in which they were eliminated.

  1. Dorothy Bundy (champion)
  2. Nancye Wynne (semifinals)
  3. Thelma Coyne (quarterfinals)
  4. Joan Hartigan (quarterfinals)
  5. Nell Hopman (semifinals)
  6. May Hardcastle (quarterfinals)
  7. Dorothy Stevenson (finalist)
  8. Do Workman (quarterfinals)

Draw

Key

Finals

Quarterfinals Semifinals Finals
               
1 Dorothy Bundy 6 6
6 May Hardcastle 3 4
1 Dorothy Bundy 6 6
5 Nell Hopman 2 3
3 Thelma Coyne 4 2
5 Nell Hopman 6 6
1 Dorothy Bundy 6 6
7 Dorothy Stevenson 3 2
2 Nancye Wynne 6 6
8 Dorothy Workman 4 3
2 Nancye Wynne 3 3
7 Dorothy Stevenson 6 6
4 Joan Hartigan 3 6 1
7 Dorothy Stevenson 6 1 6

Earlier rounds

Section 1

First round Second round Quarterfinals Semifinals
1 Bundy 6 8
Walters 3 6
1 Bundy 6 6
6 Hardcastle 3 4
6 Hardcastle
Blick w/o
1 Bundy 6 6
3 Coyne 6 6 5 Hopman 2 3
Woods 2 0 3 Coyne 6 6
O'Halloran O'Halloran 3 4
Cox w/o 3 Coyne 4 2
5 Hopman 6 6 5 Hopman 6 6
Stern 1 2 5 Hopman 6 6
Mauger 6 0 6 Mauger 2 1
Coate 1 6 4

Section 2

First round Second round Quarterfinals Semifinals
2 Wynne 6 6
Weston 2 1 2 Wynne 6 6
Vickery 6 6 Vickery 4 3
Bond 2 0 2 Wynne 6 6
8 Workman 6 6 8 Workman 4 3
Stevenson 1 3 8 Workman 6 6
Wilson 9 6 Wilson 2 1
Skinner 7 3 2 Wynne 3 3
7 Stevenson 6 6
4 Hartigan 7 6
Chitty 5 2
4 Hartigan 3 6 1
7 Stevenson 6 1 6
7 Stevenson 6 4 6
Westacott 4 6 3

References

  1. ^ "Americans invincible". The Age. No. 25, 831. Victoria, Australia. 31 January 1938. p. 15 – via National Library of Australia.
  • [1] Source for the draw at ausopen.com