1840 United States presidential election in Massachusetts|
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Turnout | 66.7%[1] 23.3 pp |
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County Results
Harrison
40–50%
50–60%
60–70%
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Van Buren
40–50%
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A presidential election was held in Massachusetts on November 9, 1840 as part of the 1840 United States presidential election.[2] Voters chose 14 representatives, or electors to the Electoral College, who voted for President and Vice President.
Massachusetts voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Massachusetts by a margin of 16.16%.
Results
See also
References
- ^ Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
- ^ Dubin, Michael J. (2002). United States Presidential Elections, 1788–1860: The Official Results by County and State. Jefferson, NC: McFarland & Co. p. xvi.
- ^ "1840 Presidential General Election Results – Massachusetts". U.S. Election Atlas. Retrieved December 23, 2013.
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- See also
- Presidential elections
- Senate elections
- House elections
- Gubernatorial elections
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