1788–89 United States presidential election in Delaware

Main article: 1788–89 United States presidential election
1788–1789 United States presidential election in Delaware
January 7, 1789
 
Nominee George Washington John Jay
Party Independent Independent
Home state Virginia New York
Electoral vote 3 3
President before election

Office established

Elected President

George Washington
Independent

The 1788–89 United States presidential election in Delaware took place on January 7, 1789, as part of the 1788–1789 United States presidential election to elect the first President. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

George Mitchell, John Baning, and Gunning Bedford Jr. served as electors. George Washington and John Jay both received three electoral votes.[1][2]

Results

1788–89 United States presidential election in Delaware[2]
Party Candidate Votes % ±%
Federalist George Mitchell 522
Federalist Gunning Bedford Jr. 163
Federalist John Banning [a]
Total votes >685 100.00%

See also

References

  1. ^ Jensen & Becker 1976, p. xxviii.
  2. ^ a b c "City and County Statistics". Tufts University. Archived from the original on September 2, 2024.

Notes

  1. ^ Kent County unanimously voted in favor of John Banning.[2]

Works cited


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